Question

What is the solution set to log8(4x + 2) + 4 ≥ 5?

Answer 1

Your answer is A

distribute the 8 to the 4x and 2 which gives you
=32x + 16 + 4 >_ 5
now you need to add the 16 and the 4
which leaves you with
=32x + 20 >_ 5
then subtract the 20 from both sides
then you have
=32x >_ -15
then divide 32 from both sides with gives you
x>_ -15/32 or x>_ -0.5

Answer 2

Answer:  B) [1.5, ∞)

Step-by-step explanation:

log₈ (4x + 2) + 4 ≥ 5

log₈ (4x + 2)       ≥ 1               subtract 1 from both sides

       4x + 2         ≥ 8¹             apply log rules

       4x               ≥ 6              subtracted 2 from both sides

                       x ≥ 1.5            divided 4 from both sides

In interval notation:   [1.5, ∞)

1.5 is included so use the bracket.

It is "greater than" so it goes to infinity (which uses a parenthesis)