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Goshia [24]
3 years ago
14

What is the solution set to log8(4x + 2) + 4 ≥ 5?

Mathematics
2 answers:
Oksanka [162]3 years ago
5 0
Your answer is A

distribute the 8 to the 4x and 2 which gives you
=32x + 16 + 4 >_ 5
now you need to add the 16 and the 4
which leaves you with
=32x + 20 >_ 5
then subtract the 20 from both sides
then you have
=32x >_ -15
then divide 32 from both sides with gives you
x>_ -15/32 or x>_ -0.5
jenyasd209 [6]3 years ago
3 0

Answer:  B) [1.5, ∞)

<u>Step-by-step explanation:</u>

log₈ (4x + 2) + 4 ≥ 5

log₈ (4x + 2)       ≥ 1               <em>subtract 1 from both sides</em>

       4x + 2         ≥ 8¹             <em>apply log rules</em>

       4x               ≥ 6              <em>subtracted 2 from both sides</em>

                       x ≥ 1.5            <em>divided 4 from both sides</em>

In interval notation:   [1.5, ∞)

<em>1.5 is included so use the bracket. </em>

<em>It is "greater than" so it goes to infinity (which uses a parenthesis)</em>

                                       

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