Answer:
2/5
Step-by-step explanation:
0.4 = 4/10 which in simplest form is 2/5
Answer:
no solutions
Step-by-step explanation:
Since the two terms have the same base, we are able to use the rule for subtracting logarithms:

Therefore, the equation can be written as:

By using the definition of a logarithm we can say that:

When plugging this solution in, you find that the term
has x-6 evaluate to a number less than 0. This is not included in the domain of log functions, so
is not a valid solution. This means that there are no solutions.
Start with parentheses first
Afterwards do exponents
Next do either multiplication or division (L to R)
Then Addition and Subtraction (L to R)
__________________________________________
Then solve to find your answer
Answer: a the first answer is right
Answer:
The probability that a randomly chosen tree is greater than 140 inches is 0.0228.
Step-by-step explanation:
Given : Cherry trees in a certain orchard have heights that are normally distributed with
inches and
inches.
To find : What is the probability that a randomly chosen tree is greater than 140 inches?
Solution :
Mean -
inches
Standard deviation -
inches
The z-score formula is given by, 
Now,





The Z-score value we get is from the Z-table,


Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.