The fish population in a lake decreases by 2% each year. What is the common ratio? –0.02 –0.98 0.02 0.98
2 answers:
Answer:
D. 0.98
Step-by-step explanation:
We have been given that the fish population in a lake decreases by 2% each year. We are asked to find the common ratio.
The fish population is decreasing 2% each year. This means that each next year the fish population is 98% (100-2) of the fish population of last year.
So the common ration would be 98%. Upon converting 98% in decimal we will get,
Therefore, common ration is 0.98 and option D is the correct choice.
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Step-by-step explanation:
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Answer:
The value of P (A ∩ B) is 0.25.
Step-by-step explanation:
Independent events are those events that do not effect the occurrence of each other, i.e. if event <em>X </em>and <em>Y</em> are independent then the occurrence of <em>X</em> and <em>Y </em>are not influenced by each other.
For independent events <em>X</em> and <em>Y</em> the joint probability of <em>X</em> and <em>Y</em> is:
It is provided that events <em>A</em> and <em>B </em>are independent of each other.
And P (A) = P (B) = 0.50.
Compute the value of P (A ∩ B) as follows:
Thus, the value of P (A ∩ B) is 0.25.