If P=(-2,5) and (x,-27), find all numbers x such that the vector represented by PQ has length -40
1 answer:
Answer:
x ∈ {-26, 22}
Step-by-step explanation:
A graph shows that the points (-26, -27) and (22, -27) lie on a circle of radius 40 centered at (-2, 5). That is, if Q is either one of these points, the vector PQ will have a length of 40:
- √((-26-(-2))^2 +(-27-5)^2) = √((-24)^2 +(-32)^2) = √1600 = 40
- √((22 -(-2))^2 +(-27 -5)^2) = √(24^2 +(-32)^2) = √1600 = 40
You can call it -40 if you like, but you have to define what negative length means when you do that.
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Answer:
6
Step-by-step explanation:
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