Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
What are you supposed to do?
Answer:

Step-by-step explanation:
we know that
The equation of the line in standard form is in the form

where
A is a positive integer, and B, and C are integers
In this problem we have
----> equation of the line in slope intercept form
Convert to standard form
Multiply by 5 both sides


Answer:
La respuesta es falso.
Step-by-step explanation:
La respuesta es falso.
Cuando se suman fraccciones con igual denominador, se suman los numeradores (numerador con numerador) y se deja el mismo denominador (el cual es común en ambos). Por ejemplo, la suma de 1/5 + 3/5 da como resultado:

En el caso de fracciones con diferentes denominadores, tampoco se suma numerador con numerador y denominador con denominador. En ese caso se debe encontrar el mínimo común múltiplo.
Por lo tanto, la respuesta es falso.
Espero que te sea de utilidad!