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mash [69]
3 years ago
7

A rectangle has perimeter 84cm and length 35cm. What is its width?

Mathematics
2 answers:
harina [27]3 years ago
8 0
We know a rectangle has 4 sides, 2 longer and 2 shorter. If one side is 35 cm, then we know that another side is also 35cm. So, the lengths of 2 of the sides are 70 cm together. We have 14 cm left. Divide 14 by 2. The other 2 sides are 7 cm wide.
horsena [70]3 years ago
5 0
Perimeter is 2 length + 2 width so 84=2(35) + 2(width)
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Can someone please help me on this?
jonny [76]

Answer:

ABCD is a parallelogram. True or False

True, opposite sides are parallel and equal

ABCD is a Rhombus. True or False

True, all sides of the shape are equal, and opposite angles are equal. The shape meets all requirements to be a Rhombus.

ABCD is a Rectangle. True or False

True, opposite sides are the same length and there are 4 right angles

Step-by-step explanation:

You will have to plot the points but here you go

3 0
3 years ago
Phoebe and finn are sharing
pychu [463]

Answer:

Let's define:

P = pies that Phoebe ate

F = pies that Finn ate

We know that together they ate 29/12 pies, then:

P + F = 29/12

We know that Finn ate more than Phoebe, then F > P.

And we know that Phoebe ate more than 5/6 of a pie, then:

P > 5/6.

Then we have the relations:

P + F = 29/12

P > 5/6

F > P

To find different combinations we can just give one of the variables a value.

We have a direct condition on P, which is:

P > 5/6

So we can just give P any value larger than 5/6 and find the value of F.

For example:

P = 6/6 = 1

Then:

F + 1 = 29/12

F = 29/12 - 1 = 29/12 - 12/12 = 17/12

And 17/12 > 5/6

So we meet the condition F > P.

Then we have the combination:

P = 1

F = 17/12

Now let's find another condition, this time let's use:

P = 5/6 + 1/12 = 10/12 + 1/12 = 11/12

Then:

F + 11/12 = 29/12

F = 29/12 - 11/12 = 18/12

And 18/12 > 11/12

Then we meet the condition:

F > P.

We have the combination:

F = 18/12

P = 11/12

Now for the last combination, we can use:

P = 5/6 + 3/12 = 10/12 + 3/12 = 13/12

Then:

F + 13/12 = 29/12

F = 29/12 - 13/12

F = 16/12

And 16/12 > 13/12

Then we meet the condition F > P

We have the combination:

F = 16/12

P = 13/12.

5 0
3 years ago
Solve for x <br> 4(3+x)+x=x+4<br> TYYY
iris [78.8K]

\sf\longmapsto 5x + 12 = x + 4

\sf\longmapsto 5x + 12 - 12 = x + 4 - 12

\sf\longmapsto 5x = x + 4 - 12

\sf\longmapsto 5x = 4 - 12

\sf\longmapsto 5x =  - 8

\sf\longmapsto( 5x - x)

\sf\longmapsto 4x =  - 8

\sf\longmapsto  \frac{ - 8}{4}  =  - 2

5 0
2 years ago
Read 2 more answers
Use the appropriate substitutions to write down the first four nonzero terms of the Maclaurin series for the binomial (1+3x)^(-1
PolarNik [594]

Answer:

First term=1

Second term=-x

Third term=2x^2

Fourth term =-\frac{28}{3!}x^3

Step-by-step explanation:

We are given that function

f(x)=(1+3x)^{-1/3}

We have to find the  first four non zero terms of the Maclaurin series for the binomial.

Maclaurin series of function f(x) is given by

f(x)=f(0)+f'(0)x+\frac{1}{2!}f''(0)x^2+\frac{1}{3!}f'''(0)x^3+....

f(0)=(1+3x)^{\frac{-1}{3}}=1

f'(x)=-\frac{1}{3}(1+3x)^{-\frac{4}{3}}(3)=-(1+3x)^{-\frac{4}{3}}

f'(0)=-1

f''(x)=\frac{4}{3}\times 3 (1+3x)^{-\frac{7}{3}}

f''(0)=4

f'''(x)=-4\times \frac{7}{3}\times 3(1+3x)^{-\frac{10}{3}}

f'''(0)=-28

Substitute the values we get

(1+3x)^{-\frac{1}{3}}=1-x+\frac{4}{2!}x^2+\frac{-28}{3!}x^3+...

(1+3x)^{-\frac{1}{3}}=1-x+2x^2+\frac{-28}{3!}x^3+...

First term=1

Second term=-x

Third term=2x^2

Fourth term =-\frac{28}{3!}x^3

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dimaraw [331]

Answer:

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3 0
3 years ago
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