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Vinvika [58]
2 years ago
15

Given the sequence 2, 4, 8, , 16,........, where x = 0, 1, 2, 3, .......what is the function rule? f(x) = 2x + 2 f(x) = 2(2)x f(

x) = (2x) f(x) = 2
Mathematics
1 answer:
Kay [80]2 years ago
5 0

Option C: f(x)=2^x is the function rule.

Explanation:

The sequence is 2,4,8,16, \dots \dots

Let us find the common difference of this sequence.

Common ratio = \frac{4}{2} =2

Hence, r=2

Thus, the given sequence is a geometric progression.

To determine the function rule, let us substitute the values in the general formula of GP which is given by

f(x)=ar^{x-1} where a=2, r=2

Substituting we get,

f(x)=2(2)^{x-1}

Simplifying, we get,

f(x)=2\times2^x\times2^{-1

Adding the powers, we get,

f(x)=2^{1+x-1}

Simplifying, we get,

f(x)=2^x

Hence, the function rule is f(x)=2^x

Thus, Option C is the correct answer.

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Steps to solve:

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~Substitute

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~Subtract

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