Answer:
The answer is D - 3.786x10^7
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
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Two solutions:
1. x =(100-√2160)/2=50-6√ 15 = 26.762
2. x =(100+√2160)/2=50+6√ 15 = 73.238
Statement 1 : Gail bought a $45 sweater at 1/3 off.
<u>Discount in Sweater Purchase:</u>

Statement 2: Gail can use her 12% employee discount once a week and used her discount on the suit priced at $140.
Discount in Suit Purchase:

Conclusion:
<u>Discount in Suit Purchase ($16.8) is greater than Discount in Sweater Purchase ($15)</u>