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Tcecarenko [31]
3 years ago
14

The angle of elevation to the top of a 15-story skyscraper is measured to be 4 degrees from a point on the ground 2,500 feet fro

m the building. What is the height of the skyscraper to the nearest hundredth foot?
A. 83.13 feet
B. 174. 82 feet
C. 96.49 feet
174. 39 feet

Mathematics
2 answers:
madreJ [45]3 years ago
8 0
Set up a right triangle
The base will be 2,500 feet and the angle where the hypotenuse meets the base will be 4 degrees
The height is your x value,
tan4=x/2,500 
Multiply both sides by 2500
2500tan4=x
x=174.817 
The answer is B
dalvyx [7]3 years ago
5 0

Answer:

Option B 174.82\ ft

Step-by-step explanation:

we know that

In the right triangle ABC

tan(A)=\frac{BC}{AC}

see the attached figure to better understand the problem

we have that

A=4\°  

AC=2,500\ ft

BC=h\ ft ----> is the height of the skyscraper

substitute and solve for h

tan(4\°)=\frac{h}{2,500}

h=2,500*tan(4\°)=174.82\ ft

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