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2 years ago

What is the domain of the function Y = 2X-52

Mathematics

1 answer:

grigory [225]2 years ago

7 0

Answer:

x∈R

Step-by-step explanation:

Assuming the equation is y = 2x - 52, any real number will satisfy this equation - positive, negative, rationale, etc.

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How do you solve this equation and what is the answer?

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3 years ago

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3 years ago

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Find the third, fourth, and fifth terms of the sequence defined by

statuscvo [17]

By the recursive definition,

$a_3=2a_2-a_1=2\cdot9-4=14$

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2 years ago

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In the figure, GK bisects FGH

bija089 [108]

Answer:

$w = 7$

Step-by-step explanation:

Given:

m<FGK = (7w + 3)°

m<FGH = 104°

angle bisector of <FGH = GK

Required:

Value of w

SOLUTION:

Since GK bisects angle FGH, it divides the angle into two equal parts. Therefore, the following equation can be generated to find the value of w:

m<FGH = 2*m<FGK

$104 = 2*(7w + 3)$ (substitution)

Divide both sides by 2

$\frac{104}{2} = \frac{2*(7w + 3)}{2}$

$52 = 7w + 3$

Subtract 3 from each side

$52 - 3 = 7w + 3 - 3$

$49 = 7w$

Divide both sides by 7

$\frac{49}{7} = \frac{7w}{7}$

$7 = w$

$w = 7$

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3 years ago

A professor has recorded exam grades for 10 students in his class, but one of the grades is no longer readable. If the mean sco

Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

$\frac{R+x}{10} =80$

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

$\frac{R}{9} = 85\\$ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

$\frac{R}{9} = 85\\R=85*9= 765$

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

$\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35$

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3 years ago

What is the domain of the function Y = 2X-52​

What is the domain of the function Y = 2X-52