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3 years ago

What is the domain of the function Y = 2X-52

Mathematics

1 answer:

grigory [225]3 years ago

7 0

Answer:

x∈R

Step-by-step explanation:

Assuming the equation is y = 2x - 52, any real number will satisfy this equation - positive, negative, rationale, etc.

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Neko [114]

To answer this question you would need to find the surface area of this rectangular prism. In order to find the surface area you would find the areas of all six faces. The top and bottom faces would both be square with an area of 5.29 (2.3x 2.3)ft.². All for lateral faces would have areas of 8.28 (2.3x3.6)ft.². Adding these for faces along with the other two faces would give you a total surface area of 43.7 ft.². If you take away the bottom face which is not painted you will have a surface area that is going to be painted of 38.41 ft.². To determine the percentage of this rectangle or prism that is going to be painted, create a ratio of the amount painted to the total amount surface area. Divide these to create a decimal and then converted to a percent. 38.41/43.7=0.879 (87.9%).

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3 years ago

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lakkis [162]

Answer:

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Step-by-step explanation:

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3 years ago

Solve 2x2 − 12x + 20 = 0. 3 ± i 3 ± 2i 1 ± 2i 2 ± 3i

makkiz [27]

This is the concept of quadratic equations, solving the equation 2x^2-12x+20=0 using the formula we get:
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x=[-(-12+/-sqrt((-12)^2-4*2*20)]/(2*2)
x=[12+/-sqrt(144-160]/4
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3 years ago

A high school guidance counselor determined the following information regarding students and their likelihood of playing a sport

iogann1982 [59]

Conditional Probability

Given two events A and B (not excluding), the probability that A occurs given that B has occurred is called a conditional probability and is calculated as:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Where P(A∩B) is the probability that A and B occur simultaneously and P(B) is the probability that B occurs.

Now with the given data, we must find the values of the required probabilities.

30% of the students play a sport (S), this means that:

70% of the students don't play a sport (NS).

65% of the students have a job.

Note that there could be students who both play sports and have a job.

Of the 30% of the students who play a sport, 50% have a job. This means that:

15% of the students play a sport and don't have a job

15% of the students play a sport AND have a job

65% - 15% = 50% of the students have a job and don't play a sport

That last number is the numerator of the equation given above:

P(A∩B) = 0.5

The event B corresponds to students that don't play a sport (NS), thus:

P(B) = 0.7

Thus we have:

$P(A|B)=\frac{0.5}{0.7}=\frac{5}{7}$

The required probability is 5/7 or 0.7143

4 0

1 year ago

A sample of n = 4 scores is selected from a population with m = 40 with s = 8, and the sample mean is M = 43. What is the standa

vladimir2022 [97]

Standard error (SE)
$se= \frac{s}{ \sqrt{n} }$
Or

$se = \sqrt{ \frac{ {s}^{2} }{n} }$

Therefore, SE of the mean = (8)/(2) =4

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3 years ago

What is the domain of the function Y = 2X-52​

What is the domain of the function Y = 2X-52