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3 years ago

can you help me evaluate this: 7m + 14m - 6n - 5n + 2m. why do you add 6n with 5n instead of subtract?

Mathematics

1 answer:

Mademuasel [1]3 years ago

6 0

Step-by-step explanation:

The reason is because it is not just 6 it is - 6 so when there are two negative numbers they don't subtract they add if it was 6n then it was to be subtracted

21m - 11n + 2m

23m - 11n

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If 1 cm represents 35 miles what is 1.25 cm in miles?

lapo4ka [179]

Answer:

43.75 miles

Step-by-step explanation:

You divide the 35 by 4 and then just add it to the original distance of 35 miles. 35/4=8.75

8.75+35=43.75

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2 years ago

Content://media/external/file/8717

MAVERICK [17]

WEll FIRST IT WRONF THEN IT IS

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Less than 75% of workers got their job through internet resume sites. A researcher thinks it has increased.

Vera_Pavlovna [14]

Answer:

H0 : p = 0.75 against H1: p > 0.75 One tailed test.

Step-by-step explanation:

We state our null and alternative hypotheses as

H0 : p = 0.75 against H1: p > 0.75 One tailed test.

In this case H0 is not defined as p≤ 0.75 because the acceptance and rejection regions cannot be set up. Therefore we take the exact value of H0 : p= 0.75.

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3 years ago

Plz help! It's another probability question! Whoever answers correctly gets marked as brainliest!

Gelneren [198K]

Answer:

this is what I found:

Step-by-step explanation:

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3 years ago

I don't know how to do this or what i'm doing plz help

mote1985 [20]

recalling that d = rt, distance = rate * time.

we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?

$\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}$

so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.

$\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}$

$\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}$

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3 years ago