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tangare [24]
3 years ago
12

How does graphing -3/4 different from graphing 3/4

Mathematics
1 answer:
katovenus [111]3 years ago
3 0
Graph 1: y= -3/4, which means its (x,y) coordinate is (0, -3/4).

Graph 2: y= 3/4, which means its (x,y) coordinate is (0, 3/4).

Graph 1 would be the point -3/4 on the y-axis, while graph 2 would be the point 3/4 on the y-axis.

Therefore, graph 1 and graph 2 are symmetrical about the x-axis.

Hope this would help~
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Which inequality is graphed below?
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Answer:

Inequality: y ≥ 1/4x -1

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2 years ago
Simplify. (x6 y3)(−8xy2)(−6x3)
meriva
When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of <u>pemdas</u> and to make sure that we take each step carefully.

We first would <u></u><u>(first)</u> simplify the following:

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7 0
3 years ago
-5.5x+0.77=1.48 whats x
Nesterboy [21]

Answer:

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Hope this helps!

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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notka56 [123]
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3 years ago
Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th
Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:  

A=22 g is the final amount of the radioactive element

A_{o}=800 g is the initial amount of the radioactive element  

t is the time elapsed  

h=8 min is the half life of the radioactive element  

So, we need to substitute the given values and find t from (1):  

22 g=(800 g) 2^{\frac{-t}{8 min}} (2)  

\frac{22 g}{800 g}=2^{\frac{-t}{8 min}} (3)  

\frac{11}{400}=2^{\frac{-t}{8 min}} (4)  

Applying natural logarithm in both sides:  

ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}}) (5)  

-3.593=-\frac{t}{8 min}ln(2) (6)  

Clearing t:

t=41.46 min \approx 41.5 min This is the time elapsed

7 0
3 years ago
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