<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer:8(1/2x - 1/4)> 12 - 2x
a.x > 7
b.x > 7/3
c.x > 5/3
d.x > 5/3
Step-by-step explanation: Solve the inequality 12(1/2x-1/3)>8-2x
Answer:
X>-9
Step-by-step explanation:
Distribute
-5x-35<10
add 35 on both sides
-5x<45
Divide -5 on both sides and flip the sign since your dividing by a NEGATIVE number
x>-9
To be a gcf of a number, they have to all divide by it evenly
so if 2 is a gcf of 12 and 6 then 6/2=3 =whole and 12/2=6=whole so
therefor we can just introduct other factors which are not equal
just multiply 16 by 3 prime numbers or different numbers
16 times 2 =32
16 times 3=48
16 times 5=80
and that is an example
The second train will catch up with the first train in 1.6 hours
