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jeka94
3 years ago
5

Maths help PLZZ!!!

Mathematics
1 answer:
Kay [80]3 years ago
8 0

Triangle ABC is an isosceles triangle.

Solution:

Given data:

AB is parallel to CD and AC is the transversal.

∠ABC = 70° and ∠ACD = 55°

<em>If two parallel lines are cut by a transversal, then alternate interior angles are congruent.</em>

∠BAC ≅ ∠ACD

m∠BAC = m∠ACD

m∠BAC = 55°

<em>Sum of the angles in a straight line = 180°</em>

m∠ACD + m∠ACB + m∠ABC = 180°

55° + m∠ACB + 70° = 180°

m∠ACB + 125° = 180°

Subtract 125° from both sides, we get

m∠ACB = 55°

In triangle ABC,

∠BAC = 55° and ∠ACB = 55°

∠BAC = ∠ACB

<em>Two angles in the triangle are equal. </em>

Therefor triangle ABC is an isosceles triangle.

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Answer:

1,680\ g

Step-by-step explanation:

we know that

Brenda requires 480 grams of couscous for 4 people

so

using proportion

Find out how many grams of couscous she requires for 14 people

Let

x -----> the amount of grams

\frac{480}{4}\frac{g}{people}=\frac{x}{14}\frac{g}{people} \\\\x=14*480/4\\\\x=1,680\ g

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3 years ago
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3 years ago
A) prove that MQX is congruent to MRY
Viktor [21]

Answer:

Side MQ is similar to side MR.

- This is because since M is the mid point of QR, both MQ and MR are half of QR.

Angle MXQ and MYR are 90°

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- This is because angle X and Y are 90° and MQ and MR are equal.

∴ MQX is congruent to MRY.

7 0
3 years ago
What is the area of a circle if the circumference is 29
Kruka [31]

Answer:

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2 years ago
While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty percent of her
EastWind [94]

The given equation is,

3(-n+4)+5n=2n

Part 1:

Solve the above equation for n.

Using distributive property of multiplication,

\begin{gathered} -3n+3\times4+5n=2n \\ -3n+12+5n=2n \end{gathered}

Now, group the like terms.

-3n+5n-2n+12=0

Now, add the like terms.

\begin{gathered} -5n+5n+12=0 \\ 0=-12 \end{gathered}

0=-12 is a false statement.

Since we obtained a false statement, the given equation has no solution.

So, option b is correct.

Part 2:

The option (a) is n=3.

If while solving an equation, a single value is obtained for the variable, then the equation has only a single solution. If n=3 is obtained after solving the equation, then the student should chose option (a) as the answer.

The option (b) is "no solution".

While solving an equation, if we obtain an equation which is mathematically false, then the equation will have no solution. So, no solution is chosen when no value is obtained for n and the final equation is mathematically false.

The option (c) is "infinitely many solutions".

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8 0
1 year ago
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