I'm assuming the limit is supposed to be
Multiply the numerator by its conjugate, and do the same with the denominator:
so that in the limit, we have
Factorize the first term in the denominator as
The 
terms cancel, leaving you with
and the limand is continuous at 
, so we can substitute it to find the limit has a value of -1/18.
2x + 3y = 45
x + y = 10......y = 10 - x
2x + 3(10 - x) = 45
2x + 30 - 3x = 45
-x + 30 = 45
-x = 45 - 30
-x = 15
x = -15 <====
and y = 25
3y (y is the unknown number but it represents one number only... and also 3y represents 3 multiply by y)
Answer:
-4
explanation:
since there is subtraction sign in front of the negative 2 it would change into a positive 2.
-6 + 2 = -4
Answer:An absolute value inequality is solved by re-writing it as compound inequality. For example.
|x+1| < 5
Since the value inside the absolute value brackets: (x+1) can be positive or negative, it is re-written as a compound inequality as the example below.
x+1 < 5
x+1 > - 5
solve for the range of values x can be
-6 < x < 4
Step-by-step explanation: How to solve inequalities
