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Lerok [7]
3 years ago
14

What is the fifth term in the geometric sequence? 1, 2, 4, 8,

Mathematics
2 answers:
olga55 [171]3 years ago
8 0

Answer:

16

Step-by-step explanation:

jenyasd209 [6]3 years ago
6 0
It is 16 (it has to be 20 characters )
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How to solve this equation 15(6-g)
NikAS [45]
<span>15<span>(<span>6−g</span>)</span></span><span>=<span><span>(15)</span><span>(<span>6+<span>−g</span></span>)</span></span></span><span>=<span><span><span>(15)</span><span>(6)</span></span>+<span><span>(15)</span><span>(<span>−g</span>)</span></span></span></span><span>=<span>90−<span>15g</span></span></span><span>=<span><span>−<span>15g</span></span>+<span>90</span></span></span>
7 0
3 years ago
Please helpppp. I hate math
nikitadnepr [17]

Answer:

A

Step-by-step explanation

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6 0
3 years ago
How many 4 ounces bags of peanuts can be filled from a 5 pound bag of peanuts?
cestrela7 [59]
16 oz = 1 lb

4 bags per pound
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5 0
4 years ago
Read 2 more answers
The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured
FrozenT [24]

Answer:

The p value obtained was a low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of of driver fatalities related to alcohol is less from 0.77 or 77%.  

Step-by-step explanation:

1) Data given and notation n  

n=53 represent the random sample taken

X=35 represent the automobile driver fatalities in a certain county involved with an intoxicated driver

\hat p=\frac{35}{53}=0.660 estimated proportion of automobile driver fatalities in a certain county involved with an intoxicated driver

p_o=0.77 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the population proportion of driver fatalities related to alcohol is less than 77% or 0.77 in Kit Carson:  

Null hypothesis:p\geq 0.77  

Alternative hypothesis:p < 0.77  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.660 -0.77}{\sqrt{\frac{0.77(1-0.77)}{53}}}=-1.903

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This methos is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is an unilateral lower test the p value would be:  

p_v =P(z  

So the p value obtained was a low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of of driver fatalities related to alcohol is less from 0.77 or 77%.  

8 0
3 years ago
7^x=6^(x+7)
kondor19780726 [428]
If you have a graphing calculator you’d want to use log and it will pretty much give you the answer
4 0
4 years ago
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