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Lerok [7]
3 years ago
14

What is the fifth term in the geometric sequence? 1, 2, 4, 8,

Mathematics
2 answers:
olga55 [171]3 years ago
8 0

Answer:

16

Step-by-step explanation:

jenyasd209 [6]3 years ago
6 0
It is 16 (it has to be 20 characters )
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(help)Name the intersection of the two planes in the image below.
serg [7]

Answer:

XZ

Step-by-step explanation:

The intersection of the 2 planes is along the line XZ

3 0
3 years ago
2. Let f(x) = 3x² -x+5, find f(x+1)​
Anna11 [10]

Answer:

f(x + 1) = 3x² + 5x + 7

Step-by-step explanation:

To find f(x + 1), substitute x = x + 1 into f(x), that is

f(x + 1) = 3(x + 1)² - (x + 1) + 5 ← expand (x + 1)² using FOIL

           = 3(x² + 2x + 1) - x - 1 + 5 ← distribute parenthesis by 3

           = 3x² + 6x + 3 - x - 1 + 5 ← collect like terms

           = 3x² + 5x + 7

8 0
3 years ago
a recipe for lasagna calls for 3 pounds of tomatoes to serve 5 people. a caterer wants to make enough lasagna to serve 110 peopl
Roman55 [17]
To do this you want to divide 110 by 5 to get 22.  Now you want to multiply 3 by 22. That means the caterer need 66 pounds of tomatoes.
5 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
A. 5<br> B. 5.5<br> C. 6<br> D. 5[2
34kurt
Answer is D 5]2 that's wut I know
8 0
3 years ago
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