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sergey [27]
3 years ago
13

A line has a y-intercept at (0,4) and an x-intercept at (6,0). What is the slope of the line?

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0

Answer:

The correct answer is a. -2/3

Step-by-step explanation:

In order to find the slope of the line, use the slope formula and solve for m.

m(slope) = (y2 - y1)/(x2 - x1)

m = (4 - 0)/(0-6)

m = 4/-6

m = -2/3

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Find y. Question attatched.
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Answer: y=4

Step-by-step explanation:

We have a khown angle wich is 30 degree .

Cos 30 = root square of 3 /2

So root sqaure of 3/2 = 4 root square 3 / x

X= 4 r.sq 3 / r.sq 3/2 = 8

So we just need to apply the pythagorian theorem

X^2= y^2+ 48

64 = y^2 +48

Y^2 = 16

Y=4

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4 years ago
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3 years ago
What is the answer I need help!!
Ganezh [65]
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Some group insurance plans cover ordinary doctor visits and dental work. T or F
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4 years ago
Read 2 more answers
100.
Ratling [72]

Check the picture below.

so our bases are "d" and "d+a+b", and a height of "c".

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{parallel~sides}{bases}\\ h~~~=height\\ \cline{1-1} x=d\\ y=d+a+b\\ h=c\\ A=(d+b)c \end{cases}\implies (d+b)c=\cfrac{c[d+(d+a+b)]}{2} \\\\\\ 2(d+b)c=c[d+(d+a+b)]\implies 2dc+2bc=c(2d+a+b)

\bf ~~\begin{matrix} 2dc \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+2bc=~~\begin{matrix} 2dc \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+ac+bc\implies 2bc=ac+bc\implies 2bc=c(a+b) \\\\\\ \cfrac{2b~~\begin{matrix} c \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} c \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=a+b\implies 2b=a+b\implies 2b-b=a\implies \blacktriangleright b=a \blacktriangleleft

8 0
4 years ago
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