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3 years ago

Find the sum of 5m+3n+p,-5p+3n,and 2n-m

Mathematics

1 answer:

nordsb [41]3 years ago

8 0

$(5m+3n+p)+(-5p+3n)+(2n-m)\\\\=5m+3n+p-5p+3n+2n-m\\\\=(5m-m)+(3n+3n+2n)+(p-5p)\\\\=\boxed{4m+8n-4p}$

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4 years ago

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Please help me with this problem, please

Harman [31]

Answer:

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Step-by-step explanation:

Trig ratios:

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where $\theta$ is the angle, O is the measure of the side opposite the angle, A is the measure of the side adjacent to the angle and H is the hypotenuse, of a right triangle

We have been given the measures of the two legs, so we can find the measure of the hypotenuse by using Pythagoras' Theorem $a^2+b^2=c^2$

(where a and b are the legs and c is the hypotenuse of a right triangle)

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$\implies sin(x)=\dfrac{5}{13}$

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Step-by-step explanation:

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3 years ago

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