Let cos x = a, then
2a^2 + a - 1 = 0,
solving the quadratic equation, we have:
a = 0.5 or -1.
i.e. cos x = 0.5 or cos x = -1
for cos x = 0.5,
x = pi/3, 2pi - pi/3 = pi/3, 5pi/3
for cos x = -1,
x = pi
therefore, x = pi, pi/3, 5pi/3
Answer: B
-3(x-1)/x would be your answer
Answer:
HOW DO WE FIND IT BRO
Step-by-step explanation:
Answer:
f(2) = - 16
Step-by-step explanation:
Given
f(x) = -
To evaluate f(2) substitute x = 2 into f(x)
f(2) = - = - 16
Answer:
C) y = x-2
Step-by-step explanation:
0-2= -2
2-2= 0
3-2= 1
4-2= 2
And all of that checks out because the values I just got for y are the same as the table
hope this helps chu <3