Answer: Choice B) I and II only
The mean and median are considered measures of center as they represent the average of a data set. The average basically being a point that collectively speaks for all of the data. For example, if you have a group of basketball players whose heights range from 5'11" to 6'9", then there is no single height to report; however, we can compute the average to get a basic idea of the single height. The interquartile range (IQR) is a measure of variability or spread of the data. The higher the IQR, the more spread out the data is. Recall that 50% of the data is represented by the IQR and that IQR = Q3 - Q1 where Q1 and Q3 are the first and third quartiles respectively. So because the IQR is a measure of spread, it is not considered a center point.
Hello from MrBillDoesMath!
Answer:
Choice B.
Discussion:
From the first step
324 x^6 y^ 8 =
2^2 * 3^4 * x^2 * x^4* y^8
so the fourth root of this is
2 ^(2/4)* 3^(4/4) x^(2/4)* x^(4/4)*y^(8/4) =
2^ (1/2) * 3^1 * x^(1/2) * x^(1)* y^ (2) =
(2x)^(1/2) * 3 * x * y^2 =
3 * x * y^2 * sqrt(2x) =
3 * x * y^2 * ( (2x)^2) ^ (1/4)) =
3 * x * y^2 * (4x^2) ^ (1/4)
which is choice B
Thank you,
MrB
2w - 2
w = 5
2(5) - 2
10 - 2 = 8
The value would be 8
Angle 1 and 2 are <u>supplementary</u> angles.
