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77julia77 [94]
3 years ago
15

A candidate for class president received at least 4 times as many votes as his opponent did. If the winning candidate received a

t least 716 votes, which inequality could be used to find how many votes his opponent received?
Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

4x ≤ 716

Step-by-step explanation:

(say x = # of votes the opponent received)

Since the winning candidate got at least 716 votes, we can know that there will be <em>a greater than or equal to sign, and that the greater side will point to the 716</em>: <em>ₙ ≤ 716</em>.

Also, if the winning candidate got exactly 716 votes, then that equation will look like this: <em>4x = 716</em>. We can use that left side into our inequality: 4x ≤ 716.

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A {1,2,3,4}<br> B {2,4,9,16}<br> C {1,2}<br> D {1,2,3,4,9,16}
MaRussiya [10]

Answer:

B

Step-by-step explanation:

The range of the function consists of the set of output values ( on the right).

So its {2 4 9 16}

7 0
3 years ago
Read 2 more answers
A right triangle has one leg with a length of 48 and a hypotenuse with a length of 80. What is the length of the other leg?
Fofino [41]
Pythagoras Theroem.
Leg₁²+leg₂²=hypotenuse²

Data:
Leg₁=48
hypotneuse=80

(48)²+ leg₂²=(80)²
2304+leg₂²=6400
leg₂²=6400-2304
leg₂²=4096
leg₂=√4096
leg₂=64

Answer: B.  64
8 0
3 years ago
Help please!!! Thank you
Anna11 [10]

Answer: ∠ABE=20°

Step-by-step explanation:

∵ AB=BC

∴ ΔABC is a isosceles triangle

∵ ∠A=30

∴ ∠C=30

∵ The interior angle sum of triangle is 180°

∵ ∠A+∠B+∠C=180

    30+∠B+30=180

           ∠B+60=180

                  ∠B=120 (∠ABC)

∵ ∠EBD+∠ABE+∠ABC=linear pair

∴∠EBD+∠ABE+∠ABC=180°

                  4x+2x+120=180

                        6x+120=180

                                6x=60

                                  x=10

∠ABE=2x=2(10)=20°

Hope this helps!! :)

Please let me know if you have any question

6 0
3 years ago
Please help me I’m so lost
kogti [31]

Answer:

331.4

Step-by-step explanation:

Side length (a)

8.284

yd

Perimeter

66.27

yd

Area

331.4

yd²

Longest diagonal (l)

21.65

yd

Medium diagonal (m)

20

yd

Shortest diagonal (s)

15.307

yd

Circumcircle radius (R)

10.824

yd

Incircle radius (r)

10

yd

8 0
3 years ago
Read 2 more answers
Line L1, L2 and L3 are in the same plane, L1 is perpendicular to L2, and L3 is parallel to L1. which of the following statement
exis [7]
Only Statement 2 is surely correct.
because there maybe chances that the line L1 and L3 lies above the line L2 and they can also fulfill the condition of perpendicularity so we can't be sure about statement 3 & statement 1 is clearly incorrect
7 0
3 years ago
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