All categories

3 years ago

How do you solve this inequality; 1/3x>-2?

Mathematics

1 answer:

Kisachek [45]3 years ago

4 0

1/3x>-2=1>3x.-2
=1>-6x
=-1/6>x

You might be interested in

What happens if you subtract the two equations and solve for S5? Can you use this information to come up with a way to find any

bulgar [2K]

Step-by-step explanation:

¿Puedes decirnos las ecuaciones?

6 0

3 years ago

Hat is the metric system prefix for the quantity 0.000 001?

mezya [45]

In the metric system, you give a name to the following multiples: 10, 100, 1000, 0.1, 0.01, 0.001, and then you skip three places. So, you have

$\left.\begin{array}{cc}\vdots&\vdots\\1000000&\text{mega}\\1000&\text{kilo}\\100&\text{hecto}\\10&\text{deca}\\0.1&\text{deci}\\0.01&\text{centi}\\0.001&\text{milli}\\0.000001&\text{micro}\\\vdots&\vdots\\\end{array}\right.$

And thus 0.000001 of something is a micro-something (i.e. one millionth of a certain unit)

3 0

3 years ago

Tanisha was asked to write an example of a linear relationship she wrote this my dog sitting service charges an initial $8.00 fe

stich3 [128]

1. 15.50
2. 23.00
3. 30.50
4. 38.00

5 0

2 years ago

INEQUALITIES-PLEASE HELP! Tricia receives a $5 allowance every week. She also earns $6.50 for every hour that she baby-sits. Nex

Zinaida [17]

Answer:

6.50x + 5 = 21.25 is the answer

Step-by-step explanation:

x=2.5

4 0

3 years ago

janelle wishes to finance a car for $33,000. the bank's annual interest rate is 3.5%, and she can choose between durations of fi

Harman [31]

Answer:

For a duration of 5 years, Monthly Payment =$600.42

For a duration of 6 years, Monthly Payment =$508.83

Step-by-step explanation:

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\$

where a= Amount to Finance=$33,000

Annual interest rate = 3.5%=0.035

r=Monthly Interest Rate= 0.035 ÷ 12 = $\frac{7}{2400}$

n=number of months to pay

For a duration of 5 years

n=5X12=60 months

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\\\P=\dfrac{33000 X\frac{7}{2400} (1+\frac{7}{2400} )^{60}}{(1+\frac{7}{2400})^{60}-1} \\=\dfrac{96.25 (1.1909)}{1.1909-1}\\=\dfrac{96.25 (1.1909)}{0.1909}\\=\dfrac{114.62}{0.1909}=\$600.42$

For a duration of 6 years

n=6X12=72 months

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\\\P=\dfrac{33000 X\frac{7}{2400} (1+\frac{7}{2400} )^{72}}{(1+\frac{7}{2400})^{72}-1} \\=\dfrac{96.25 (1.2333)}{1.2333-1}\\=\dfrac{96.25 (1.2333)}{0.2333}\\=\dfrac{118.71}{0.2333}=\$508.83$

4 0

3 years ago