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olga nikolaevna [1]
3 years ago
13

Jada plans to serve milk and healthy cookies for a book club meeting. She is preparing 12 ounces

Mathematics
1 answer:
suter [353]3 years ago
7 0

Answer:

4n=c

Step-by-step explanation: i took the quiz if this is wrong its prob a differnt

quiz the last person i answered got md at befor i didnt know what quiz she take a.

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W=4
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Six times the difference of a number and 4 is no more than 10.
sveta [45]

Answer: x = 17/3 or 5 2/3

Step-by-step explanation:

Let the number be x

ATQ

6(x -4) = 10

6x-24 = 10

6x = 10+24

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please click thanks and mark brainliest if you like :)

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‼️ASAP‼️What is the product?<br> (&lt;4) (3x2 -2) (4x2 + 5x)?
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any more help just ask :)

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3 years ago
Find x. A. 21√2 B. 7 C. 21√3 over 2 D. 21√2 over 2
kkurt [141]

Answer:

D

Step-by-step explanation:

<em>for </em><em>you </em><em>to </em><em>find </em><em>x </em><em>you </em><em>first </em><em>have </em><em>to </em><em>find </em><em>the </em><em>adjacent</em><em> </em><em>of </em><em>the </em><em>4</em><em>5</em><em>°</em><em> </em><em>angle </em><em>you </em><em>can </em><em>do </em><em>that </em><em>by </em><em>using</em><em> </em><em>the </em><em>other </em><em>triangle.</em><em>u</em><em>s</em><em>i</em><em>n</em><em>g</em><em> </em><em>the </em><em>sin </em><em>ratio</em>

<em>sin60=</em><em>opposite</em><em>/</em><em>hypotenuse</em>

<em>sin60=</em><em>a/</em><em>7</em><em>√</em><em>3</em>

<em>a</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>then </em><em>after </em><em>you </em><em>have </em><em>found</em><em> </em><em>the </em><em>adjacent</em><em> </em><em>you </em><em>can </em><em>use </em><em>the </em><em>cos </em><em>ratio</em>

<em>cos45=</em><em>adjacent/</em><em>hypotenuse</em>

<em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>x</em>

<em>cos45x/</em><em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>cos45</em>

<em>x=</em><em>1</em><em>4</em><em>.</em><em>8</em><em>4</em><em>9</em>

<em>which </em><em>is </em><em>the </em><em>same </em><em>as </em><em>2</em><em>1</em><em>√</em><em>2</em><em> </em><em>over </em><em>2</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

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3 years ago
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