Answer:
170 Mbps
Explanation:
Time taken to put data on to the link T1 = 50kB / 1 Gbps = 0.0004096
Time taken for transmission T2 = 2 milliseconds = 2 * 10-3
--> throughput = ( 1 / (1+T2/T1) ) * bandwidth of link
= ( 1 / (1 + 4.8828125) ) * 1 Gbps
= 0.16998672 * 1 Gbps
= 169.98672 Mbps
= 170 Mbps.
<span>The finished product is "output." In the electronic computer, data are the raw material or input to the computer.</span>
Answer:
int counter = 0;
String userInput = "";
while (userInput != "stop") {
print "What pet do you have? ";
userInput = readInputLine();
if (userInput != "stop" ){
counter = counter + 1;
print "\nYou have one ";
print userInput;
print ". Total # of Pets: ";
print counter;
}
}
Explanation:
not sure what programming language you use, therefore the answer is pseudocode but it should give you an idea how to implement a piece of code for this problem.
Also, from the way you described the exercise I'm not sure if you always are supposed to reply with "you have one" + the pet or if you should count how often the same pet was entered.
Answer:
this is the method of processing wood
Embedded system is considered any computer system that isn't a general-purpose pc or server.
<h3>What is an embedded system?</h3>
An embedded system is a combination of computer hardware and software designed for a specific function. Embedded systems may also function within a larger system. The systems can be programmable or have a fixed functionality.
<h3>What is embedded system and its types?</h3>
Embedded systems comprise hardware and software that work together to perform specific tasks. They rely on microprocessors, microcontrollers, memory, input/output communication interfaces, and a power supply to function
To learn more about embedded system, refer
brainly.com/question/13014225
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