A gum factory puts 18 pieces of gum in each pack. How many pieces of gum are in 48 packs

1 answer:

jolli1 [7]2 years ago

7 0

Answer:

864 pieces

Step-by-step explanation:

18 pieces x 48 packs = 864 pieces in 48 packs

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Tema [17]

Answer:

trick question, the cat is going to die anyways so forget the food

Step-by-step explanation:

4 0

3 years ago

posledela

A short story that explains the graph is a man riding a sport car.

He spent a total time of 60 s.
He initial distance covered (50 m) at a speed of 2 m/s (rate of change in section A) before making a stop (section B).
He then covered another distance (30 m) at a speed of 3 m/s (rate of change in section C) before finally stopping.
In a total of 60 s, he traveled a total distance of 80 m.

A short story that can be written for the graph is a story of a man riding a sport car. He made a stop then continued later.

Section A shows the time spent and distance traveled from his the start position to when he stopped at first.

Section B shows the time spent when he first stopped.

Section C shows the time and distance traveled before arriving at his final destination.

The following are some details and key features of the graph:

1. The rate of change in each section:

Section A rate of change = rise/run $= \frac{50 - 0}{25 - 0} = \frac{50}{25} = 2 $ m/s$

Section B rate of change = rise/run $=\frac{50 - 50}{60 - 25} = \frac{0}{35} = 0 $ m/s$

Section C rate of change = rise/run $=\frac{80 - 50}{70 - 60} = \frac{30}{10} = 3 $ m/s$

The rate of change here represents the speed at which he drove.

2. The distance traveled in each section:

Distance traveled in Section A = 50 - 0 = 50 m

Distance traveled in Section B = 50 - 50 = 0 m

Distance traveled in Section C = 80 - 50 = 30 m

3. The total distance traveled:

Total distance = 50 + 0 + 30 = 80 m

4. The total time spent traveling:

Total time spent = 70 - 0 = 60 s

In summary, a short story that explains the graph is a man riding a sport car.

He spent a total time of 60 s.
He initial distance covered (50 m) at a speed of 2 m/s (rate of change in section A) before making a stop (section B).
He then covered another distance (30 m) at a speed of 3 m/s (rate of change in section C) before finally stopping.
In a total of 60 s, he traveled a total distance of 80 m.