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Ulleksa [173]
3 years ago
8

How do you do this need help

Mathematics
1 answer:
irakobra [83]3 years ago
7 0
LGN I believe. If you look at how the ret part of the match corresponds with the next match, you can correspond the letters based on the other triangles.
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When simplified (v2 – y + 1) + (4y2 – 3y - 2) is:
olchik [2.2K]

Answer:

  D.  5y^2 - 4y - 1

Step-by-step explanation:

Combine like terms:

  (y^2 -y +1) +(4y^2 -3y -2)

  = y^2(1 +4) +y(-1-3) +(1 -2)

  = 5y^2 -4y -1

8 0
3 years ago
Help me please ???????
FinnZ [79.3K]

Answer:

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Step-by-step explanation:

5 0
3 years ago
The graph below shows a line of best fit for data collected on the distance drivers traveled as a function of time.
Klio2033 [76]

Answer:

B. y = \frac{50}{3} x

5 0
2 years ago
a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

\frac{7}{3}

=2\frac{1}{3} minutes


3 0
3 years ago
Read 2 more answers
Simplify each expression.
lutik1710 [3]

Answer:

1. 80

2. 18.9

3. 7

4. 146

5. 2

6. 4

Step-by-step explanation:

1. 6+4=10

10×8=80

2. 3.6×4.5= 16.2

16.2+2.7= 18.9

3. 3+2=5

5×2= 10

17-10=7

4. 4×3=12^2

12×12=144

144+2= 146

5. 3+2=5

5×6=30

30÷15=2

6. 5×2= 10

40÷10=4

4 0
3 years ago
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