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Paladinen [302]
3 years ago
8

In the diagram which of the following segments is congruent to segment AB

Mathematics
1 answer:
Valentin [98]3 years ago
6 0
The answer is segment cd
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I need help! I would appreciate if you show me the work! Thank you !
iVinArrow [24]

Answer:

-11 for the first one and 0 for the second one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What function equation is represented by the graph?
Ahat [919]

In the given graph, lets mark two points:

Let A = (0,-3) and B = (4,-2)

The slope of the line is given by:

m = \frac{(-2)-(-3)}{(4)-(0)}

m = \frac{-2+3}{4}

m = \frac{1}{4}

The equation of the line is given by:

(y-y_1)=m(x-x_1)

(y-(-3))=(\frac{1}{4})(x-0)

4(y+3)=x

4y+12=x

4y=x-12

y= \frac{1}{4}x-3

Therefore, the function equation represented by the graph is: f(x)= \frac{1}{4}x-3

5 0
3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
Which weighs more 2.5 pounds of rocks or 40 ounces of feathers
levacccp [35]
They both weigh the same........ 1lb = 16 oz :D
6 0
2 years ago
Read 2 more answers
Part A: Consider the equation x + 7 = 16. Which number from the set {5, 7, 9, 11} makes the equation true?
wel

Part A: Substitute/plug in each number into the equation to see which number will make the equation true.

x + 7 = 16      Plug in 5 into "x"

5 + 7 = 16

12 = 16    5 doesn't make the equation true because it equals 12 not 16

x + 7 = 16     Plug in 7 into "x"

7 + 7 = 16

14 = 16     7 doesn't make the equation true because it equals 14 not 16

x + 7 = 16     Plug in 9 into "x"

9 + 7 = 16

16 = 16             9 makes the equation true because it equals 16

Part B: Plug in 9 into "x" in the inequality to see if it still makes it true.

x + 7 < 16     [x plus 7 is less than 16]

9 + 7 < 16

16 < 16     [16 is less than 16]  The same number would not make the inequality true because 16 can't be less than itself.

To figure out which numbers satisfy the inequality, plug it into the inequality:

x + 7 < 16      Plug in 5 into "x"

5 + 7 < 16

12 < 16      5 does satisfy the inequality because 12 is less than 16

x + 7 < 16     Plug in 7 into "x"

14 < 16     7 does satisfy the inequality because 14 is less than 16

x + 7 < 16     Plug in 11 into "x"

11 + 7 < 16

18 < 16     11 doesn't satisfy the inequality because 18 isn't less than 16

3 0
2 years ago
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