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labwork [276]
2 years ago
10

In a zoo there are 21 Lions. 1/3 of them are male. How many females are in the zoo?

Mathematics
2 answers:
Ganezh [65]2 years ago
6 0

Answer:

14 females in the zoo

Step-by-step explanation:

1/3 of 21 is 7

21-7=14

Jet001 [13]2 years ago
5 0
Answer: 14 female
Explanation:
21/3= 7 male
21-7=14 female
hope it helps!
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|\Omega|=QT=42-24=18\\ |A|=ST=42-29=13\\\\ P(A)=\dfrac{13}{18}\approx72.2\%\Rightarrow \text{D}

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3 years ago
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A car is traveling at 45mph. What is the equation that models the total distance d traveled after h. What is the graph of the eq
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D=45h

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2 years ago
The Basketball team sets a goal of having at least a 7:2 Win Loss Ratio. If they play 36 games in a season, how many games must
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2 years ago
Twelve percent of U.S. residents are in their forties. Consider a group of nine U.S. residents selected at random. Find the prob
miskamm [114]

Answer:

The probability is 28 % ( approx )

Step-by-step explanation:

Since, there are only two possible outcomes in every trails ( residents are in their forties or not ),

So, this is a binomial distribution,

Binomial distribution formula,

Probability of success in x trials,

P(x)=^nC_x p^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

p and q are probability of success and failure respectively and n is the total number of trials.

Let X be the event of resident who are in his or her forties.

Here, p = 12% = 0.12,

⇒ q = 1 - p = 1 - 0.12 = 0.88,

n = 9,

Hence, the probability that two or three of the people in the group are in their forties = P(X=2) + P(X=3)

^9C_2 (0.12)^2 (0.88)^{9-2}+^9C_3 (0.12)^3 (0.88)^{9-3}

=36(0.12)^2 (0.88)^7+84(0.12)^3 (0.88)^6

=0.279266611163

\approx 0.28

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7 0
3 years ago
14 POINTS.
wel

Answer:

2.3 could, but not -0.25.

Step-by-step explanation:

It is impossible to have any probability larger than 100 or lower than 0. 2.3 is possible bc it's below 100 and above 0.

6 0
3 years ago
Read 2 more answers
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