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2 years ago

Y= 3x +5

Mathematics

2 answers:

yuradex [85]2 years ago

5 0

Answer:

y = 35

y = -25

y = x^2

Step-by-step explanation:

y = 3x + 5

a) when x = 10, what is the value of y?

y = 3x +5

y = 3(10) + 5

y = 30 + 5

y = 35

b) when x= -10 what is the value of y?

y = 3x + 5

y = 3 (-10) + 5

y = -30 + 5

y = -25

c) y = x^2

because 10^2 = 100 and -10^2 = 100

Hope this helps!

Over [174]2 years ago

3 0

Answer:

a) y = 35

b) y = -25

c) Option D

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What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

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Answer:

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General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$