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ExtremeBDS [4]
4 years ago
10

True or false two supplementary angles are also a linear pair

Mathematics
2 answers:
11111nata11111 [884]4 years ago
4 0
The answer is true A Linear Pair<span> is </span>two<span> adjacent </span>angles<span> whose non-common sides form opposite rays. The line through points A, B and C is a straight line. If </span>two angles<span> form a </span>linear pair<span>, the </span>angles<span> are </span>supplementary<span>.</span>
natta225 [31]4 years ago
3 0
True because the
hay
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The verticles of a polygon p(0,4), q(5,4), r(5.-3) and s(0,-3). What are the perimeters of the polygon
makkiz [27]

Answer:

Following are the responses to the given question:

Perimeter of polygon:

PQ = 5\\\\RS = 5\\\\PR = QS=\sqrt{74} = 8.60\\\\QR = 7

Step-by-step explanation:

In this question we calculate the perimeter of a polygon which can be defined as follows:

Using formula:

d = \sqrt{(x _2 - x_1)^2 + (y_2 - y_1)^2}

When vertices are:

P ( 0 , 4) \\\\Q(5 , 4)

x_1 = 0\\\\y_1 = 4\\\\x_2 = 5\\\\y_2 = 4\\\\PQ = \sqrt{( 5 - 0)^2 + ( 4 - 4)^2}\\\\= \sqrt{5^2 + 0^2}\\\\= \sqrt{25}\\\\= 5

R( 5 , -3) and S ( 0 , -3)x_1 = 5y_1 = -3x_2 = 0\\y_2 = -3\\RS = \sqrt{ ( 0 - 5)^2 + ( -3 - (-3))^2}\\= \sqrt{( -5)^2 + ( -3 + 3)^2}\\= \sqrt{ 25 + 0}\\= \sqrt{25}\\= 5\\P( 0 , 4)\ and\ R (5 , -3)\\x_1 = 0\\y_1 = 4\\x_2 = 5\\y_2 = -3\\PR = \sqrt{( 5 - 0)^2 + ( -3 - 4)^2}\\= \sqrt{5^2 + (-7)^2}\\= \sqrt{ 25 + 49}\\= \sqrt{74}\\= 8.60\\

Q ( 5 , 4) \ and \ S(0 ,-3)\\x_1 = 5\\y_1 = 4\\x_2 = 0\\y_2 = -3\\QS =\sqrt{ ( 0 - 5)^2 + ( -3 - 4)^2}\\= \sqrt{-5^2 + -7^2}\\= \sqrt{25 + 49}\\= \sqrt{74}\\= 8.60

Q( 5,4\ and\ R(5 , -3)\\x_1 = 5\\y_1 = 4\\x_2 = 5\\y_2 = -3\\QR = \sqrt{(5 - 5)^2 + ( -3 - 4)^2}\\=  \sqrt{0^2 + (-7)^2}\\=   \sqrt{0 + 49}\\=  \sqrt{49}\\= 7\\

4 0
3 years ago
If $5000 is invested at an interest rate of 3.396 compounded monthly for 10 years, what would be the balance in the account
saul85 [17]

Answer: D

Step-by-step explanation:

Months = 12 x 10 = 120months

100%+3.396%=103.396% / 100 = 1.03396

5000 X (1.03396)^120 = 275054.36

6 0
4 years ago
A box holds 8 red and 4 blue beads. Three beads are taken from the box and not replaced. Determine: The probability that all thr
zubka84 [21]

Answer: \dfrac{14}{55}, \dfrac{13}{55}

Step-by-step explanation:

Given

There are 8 red and 4 blue beads

Three beads were taken from the box

(i)No of ways of choosing three red beads out of 12 beads is ^8C_3

Total no of ways ^{12}C_3

Probability is

P=\dfrac{^8C_3}{^{12}C_3}=\dfrac{8\times 7\times 6}{12\times 11\times 10}=\dfrac{2\times 7}{11\times 5}\\P=\dfrac{14}{55}

(ii)atleast two beads refers to minimum two beads

There can be two possibilities (2B,1 R), (3B, 0R)

\Rightarrow P=\dfrac{^4C_2\times ^8C_1}{^{12}C_3}+\dfrac{^4C_3}{^{12}C_3}\\\\\Rightarrow P=\dfrac{6\times 8}{220}+\dfrac{4}{220}=\dfrac{52}{220}\\\\\Rightarrow P=\dfrac{13}{55}

6 0
3 years ago
Solve for u. <br><br> 26= -12u-9+7u <br><br> Simplify your answer as much as possible.
tamaranim1 [39]
Turn equation around:
7u-9-12u=26
Combine like terms:
-12u+7u=-5u
This turns equation into:
-5u-9=26
Add -9 to both sides:
-5u-9=26
+9=+9 - and + cancel out
-5u=35
Divide by -5 to get “u” by itself:
-5u=35
———— -5 And -5 cancel making
-5 =-5 “u” By itself

u= -7
Hope this helps!

8 0
3 years ago
If a brick balances evenly with three quarters of a pound and three quarters of a brick what is the weight of a whole brick?
frez [133]

Answer:

three quarters of a pound and thee quarters of a brick?

Step-by-step explanation:

You didn't state any answer choices

6 0
3 years ago
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