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labwork [276]
3 years ago
5

Keith has $100 in a savings account at the beginning of the summer. He makes $25 each week at his babysitting job. He wants to h

ave more than $350 in his savings account at the end of the summer. Write an inequality that represents this situation after x weeks. Do not include spaces in your answer. You do NOT have to solve the inequality!
Mathematics
1 answer:
viktelen [127]3 years ago
7 0

Answer:

100+25x > 350

Step-by-step explanation:

We are given the following in the question:

Keith has $100 in a savings account at the beginning of the summer.

Let x be the number of weeks he works.

He makes $25 each week at his babysitting job.

He wants to earn more than $350 dollars during summer.

Total money earned by job = 25x

His total money in account should be more than 350$.

We can write this with the help of inequality:

100+25x > 350

The following inequality represents the given situation.

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Which type of annuity typically utilizes mutual funds
Vlada [557]
Answer:
variable annuity typically provides mutual funds

Explanation:
1- Annuity is commonly used financial product among the retirees to get regular income.
2- Annuity usually pays a fixed amount each month
3- variable annuity is different because the amount of funds paid each month varies depending on how the investment performs each month.

Hope this helps :)
4 0
3 years ago
Help!!?????? Plssssss
zhannawk [14.2K]

Answer:

1st row- 27

2nd row- 18, 48

3rd row- 55

8 0
3 years ago
Read 2 more answers
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Lostsunrise [7]
Jayne will need to drive 40 mph on the way back.
4 0
3 years ago
Write an equation in slope-intercept form for the line that is parallel to y = −4x − 3 and that passes through the point (−2, 4)
Neporo4naja [7]
Since it's parallel, then the slope is the same
use the point slope formula and plug in the slope and point
y-y1=m(x-x1)
y-4=-4(x+2)
y-4=-4x-8
y=-4x-4
this is in slope intercept form
6 0
3 years ago
A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98
pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.36

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

4 0
2 years ago
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