Answer:
the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)
Step-by-step explanation:
since the variance S² of the batch follows a normal distribution , then for a sample n of 20 distributions , then the random variable Z:
Z= S²*(n-1)/σ²
follows a χ² ( chi-squared) distribution with (n-1) degrees of freedom
since
S² > 3.10 , σ²= 1.75 , n= 20
thus
Z > 33.65
then from χ² distribution tables:
P(Z > 33.65) = 0.02020
therefore the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)
2 ones and 8 hundredths
00.00
the first zero is tens, ones, and after the decimal, to the right is the tenths, hundredths and so on
Answer: 42.0
Step-by-step explanation:
That’s answer is A)-3,4) because you reflect as follows
.6 * 25 = 15
.06 * 25 = 1.5
