18. 1.5 gal/min * 60min/hr * 4qt/1gallon = 360 qt/hr
20. .85km/s * 60 s/min * 1000m/km = 51000 m/min
22. 20 oz/min * 1440 min/day * 1 qt / 32 oz = 900 qt/day
Answer:
c.My grade is 0.87 standard deviations above the mean.
Step-by-step explanation:
given that the z-score of your grade on this Statistics exam turns out to be z=0.87.
Z score is nothing but std normal variate
Any normal distribution can be converted into std normal by the transformation
Z =
Thus when z=0.87 we mean
x = Mean +0.87 sigma
Or my grade is 0.87 std deviations above the mean
Hence option C is right.
c.My grade is 0.87 standard deviations above the mean.
f) 16 - p = 12 minus 12
4 - p = 0 plus p
p = 4
g) 18 - 2p = 6 divide by -2
-9 + p = -3 plus 9
p = 6
h) p x 2 + 4 = 9 divided by 2
p + 2 = 4.5 minus 2
p = 2.5
i) p x 4 - 3 = 1 plus 3
p x 4 = 4 divided by 4
p = 1
Answer:
1/2 is the answer
Step-by-step explanation:
using the formula of slope Y2-Y1/X2- X1
5.48 x 10^4
the decimal place would need to be moved 4 to the right (hence 10^4)