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3 years ago

What is the slope !!!!!

Mathematics

1 answer:

Ratling [72]3 years ago

6 0

Hello there! Slope is rise/run. The formula for finding slope is y2 - y1/ x2 - x1, meaning that you subtract the first x and y-coordinates from the second x and y-coordinates. We'll use the points (0, 3) and (3, 2) for this case. Plug in the values into the formula to get this:

2 - 3 / 3 - 0

Subtract the values in order to get -1/3. There. The slope of the line is -1/3.

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Determine the function which corresponds to the given graph. (3 points) a natural logarithmic function crossing the x axis at ne

quester [9]

Answer:

$y =log_e(x+3)$

Step-by-step explanation:

It is given that the graph corresponds to a natural logarithmic function.

That means, the function $y$ has a natural log (Log with base $e$ ) of some terms of x.

It is given that asymptote of given curve is at $x= -3$ . i.e. when we put value

$x= -3$ , the function will have a value $y \rightarrow \infty$ .

We know that natural log of 0 is not defined.

So, we can say the following:

$log_e(x+a)$ is not defined at $x= -3$

$\Rightarrow x+a =0\\\Rightarrow x = -a$

i.e. $x =-a$ is the point where $y \rightarrow \infty$

a = 3

Hence, the function becomes:

$y =log_e(x+3)$

Also, given that the graph crosses x axis at x = -2

When we put x = -2 in the function:

$y =log_e(-2+3) = log_e(1) = 0$

And y axis at 1.

Put x = 0, we should get y = 1

$y =log_e(0+3) = log_e(3) \approx 1$

So, the function is: $y =log_e(x+3)$

4 0

3 years ago

Find chase's mistake

alekssr [168]

This is no mistake he is the one

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3 years ago

Solve for m. <br> 2(5m + 4) = 2 (3m - 10)

agasfer [191]

2(5m+4)=2(3m-10)
10m+8= 6m-20
-6m -6m
4m+8= -20
-8 -8
4m= -28
m = -7

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3 years ago

Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$

KengaRu [80]

$\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy$
$\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy$
$\displaystyle=-\frac12\int_{y=0}^{y=2\pi}(\cos3y-2\cos2y+\cos y)\,\mathrm dy$
$\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}$
$=0$

4 0

3 years ago

What ordered pair is the solution to -7x+3y=2

goldenfox [79]

Answer:

Step-by-step explanation:

3y=7x+2

$y=\frac{7x+2}{3}\\x=1,y=3\\$

one pair is (1,3)

go on adding 3 in x=1,you get corresponding value of y.

x=4,y=10,(4,10)

and so on .

7 0

3 years ago