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klasskru [66]
3 years ago
6

Members of the Science Club went to a history museum. It cost $7.25 for each member of the club. If 90 members went to the museu

m, how much would the total cost be?
Mathematics
1 answer:
malfutka [58]3 years ago
5 0
652 I believe or something close to that.
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Do you think there are any ordered pairs that are solutions to BOTH y = x + 5 and y = –2x – 1? Explain.
zloy xaker [14]

Answer:

The ordered pair is (-2,3)

Step-by-step explanation:

y=x+5\\y=-2x-1\\\implies x+5=-2x-1\\\implies 3x=-6\\\boxed{x=-2}\\\implies y=-2+5=\boxed {3}\\

8 0
3 years ago
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If a company uses $1,410 of its cash to purchase supplies, the effect on the accounting equation would be:
grin007 [14]

The above mentioned transaction will affect the Assets side of the accounting equation or the Assets side of the balance sheet

Since we use cash of $1,410 the cash account would be debited with $1,410. In other words cash will be reduced by $1,410

Since the cash is used to purchase supplies, the inventory will be credited with $1,410. This means the inventory would be increased by $1,410.

Hence in conclusion, the two accounting activities would be a debit of $1,410 on cash and a credit of $1,410 on the inventory. So the net of the Assets remains unchanged.

4 0
3 years ago
What percentage of the Cherry Hill residents polled supported Gartman?
zimovet [89]

Answer:

D. About 48%

I hope this helps!

5 0
3 years ago
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What is 499 divided by 2? And show steps too
givi [52]
The answer would be 249 with a remainder of 1

You would first put the 2 over the 4, as 2 times 2 is 4. Bring the 9 down. 2 goes into 9 about 4 times, but it has the remainder of 1. You bring the other 9 down, and now it says 19. 2 x 9 equals 18, so you put the 9 on top and there you have 249 with the remainder of 1. 
6 0
3 years ago
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Kurt drew a rectangular maze with the length of 3/4 foot and a width of 5/12 foot.What is the area,in square feet,of Kurt's maze
nata0808 [166]
Answer: \cfrac{5}{16} \textnormal { ft}^2


Explanation:

\textnormal {Area} =  \cfrac{3}{4}  \times \cfrac{5}{12}

\textnormal {Area} = \cfrac{5}{16} \textnormal { ft}^2
4 0
3 years ago
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