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andreev551 [17]
1 year ago
7

Write a fact family for each set of numbers.

Mathematics
1 answer:
tatyana61 [14]1 year ago
4 0

Answer: in every case, the first two number multiplied equal the third number, I don't quit understand if that's the answer you were looking for,

but that's the first thing that occurred to me

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Who ever answers this first will get a brainlest
Mrac [35]

Answer:

Well assuming you don’t need to simplify

44/100

0.44

44%

Step-by-step explanation:

Okay so fraction is easy, theres a 100 cubes in total, 44 are shaded in, 44/100 are shaded in which is the area in this scenario.

Decimal is basically moving the place area by a specific amount, in this case theres no whole number since the whole number is 1 or 100/100 and its 44/100 right now so it can’t be a whole number. Decimals go by tenths, hundreths, thousandths, etc. so in this case 44/100 is n the hundreth place since its over a hundred so its 0.44. Or you can move it twice to the right by the times of 0 that appears.

Percent basically means out of 100. So in this case its 44 out of a hundred or 44%

7 0
3 years ago
Read 2 more answers
What is the equation of the following line? Be sure to scroll down first to see
likoan [24]

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{-1}{0+3}\implies -\cfrac{1}{3}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-\cfrac{1}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=-\cfrac{1}{3}(x+3) \\\\\\ y-1=-\cfrac{1}{3}x-1\implies y=-\cfrac{1}{3}x

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
FREE POINTS
Nonamiya [84]
2 please pick me!!!!
5 0
4 years ago
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The quotient of 6 divided by the difference of m minus 3<br>A.15<br>B.2<br>C.3<br>D.21<br>E.42​
anzhelika [568]
A i hope this helps!!
6 0
3 years ago
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