The possible values of x for the following functions are values on real number except 0 and 1
<h3>Domain of a function</h3>
The domain of a function are the values of the independent variable for which it exists.
Given the function below
f(x)=2-x/x(x-1)
The function does not exist at the. point where the denominator is zero. From the function given, the function does not exist when;
x(x -1) = 0
x = 0 and x = 1
Hence the possible values of x for the following functions are values on real number except 0 and 1
Learn more on domain of a function here; brainly.com/question/1770447
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Answer:
<h2>0.00390625 /
</h2>
Step-by-step explanation:
so you are saying do:
which is 16 /4096
16/4096=0.00390625
<u>another way you can do this is</u>
just subtract the powers
2-6=-4
so the answer is
Answer:
0
Step-by-step explanation:
Assuming the problem is:
"lim x-> 4 f(x)=5 lim x-> 4 g(x)=0 and lim x-> 4 h(x)=-2, then find lim x->4 (fg)(x)"
lim x->4 (fg)(x)
Since we know the limits of f and g at x=4 exist we can write the limit as:
lim x->4 f(x) lim x->4 g(x) (since fg(x) means f times g of x.)
5(0)
0
C=2πr
75=2 (3.14) (r)
75 = (6.28) (r)
r= 11.942675
rounded to the nearest foot is 12.
