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xeze [42]
3 years ago
12

A balloon is 300 feet above a cliff. The angle of depression to the cliff edge is 40° 30'. What is the horizontal distance from

the balloon to the edge of the cliff?
a. 462 feet
b. 392 feet
c. 351 feet
d. 256 feet
Mathematics
1 answer:
photoshop1234 [79]3 years ago
3 0
May be the vertical distance is 300.
and let horizontal distance be h.
angle of depression (from the balloon) to edge of cliff = 40.5°
so,
tan(40.5)=h/300
h= 300*tan(40.5)
since, tan(45°)=1, tan(40.5°) must be smaller than one as tan(x) is a increasing function.
so 300*tan(40.5°) must be less than 300
therefore the horizontal distance is 256 ft
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Answer:

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

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After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

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This means that P(X \leq 0.62) = 0.99180.

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