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xeze [42]
4 years ago
12

A balloon is 300 feet above a cliff. The angle of depression to the cliff edge is 40° 30'. What is the horizontal distance from

the balloon to the edge of the cliff?
a. 462 feet
b. 392 feet
c. 351 feet
d. 256 feet
Mathematics
1 answer:
photoshop1234 [79]4 years ago
3 0
May be the vertical distance is 300.
and let horizontal distance be h.
angle of depression (from the balloon) to edge of cliff = 40.5°
so,
tan(40.5)=h/300
h= 300*tan(40.5)
since, tan(45°)=1, tan(40.5°) must be smaller than one as tan(x) is a increasing function.
so 300*tan(40.5°) must be less than 300
therefore the horizontal distance is 256 ft
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3(x - 1)(x + 3)(x + 2)

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Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and
MatroZZZ [7]
<h2>Hello!</h2>

Since there is no additional information, we can assume that the given angles are respect to the horizontal axis (x), so

The answer is:

Magnitude: 95.14 lbs

Direction: 80° respect to the x-axis

<h2>Why?</h2>

Since there is no additional information about the given angles, we can assume that both angles are respect to the horizontal axis (x), positive direction to x-axis positive directions (right) and above x-axis.

<h2>Calculations:</h2>

100 pounds (lb) force, 50° angle:

100lbs*cos(50)=64.28lbs\\100lbs*sin(50)=76.60lbs

50 pounds (lb) force, 160° angle:

50lbs*cos(160)=-46.98lbs\\50lbs*sin(160)=17.10lbs

So,

For x-axis forces we have:

64.28lbs (positive direction)

-46.98lbs (negative direction)

Then,

64.28lbs-46.98lbs=17.3lbs (positive direction)

Fox y-axis forces we have:

76.60lbs (positive direction)

17.10 lbs (positive direction)

Then,

76.60lbs + 17.10 lbs =93.7lbs (positive direction)

So, we have the two components values of the acting force:

17.3 lbs for the x-axis and 93.7 lbs for the y-axis.

Therefore,

We have to calculate the angle between both resultant force components:

Let's calll it α

So,

\alpha=tan^{-1}(\frac{y-axisValue}{x-axisValue})=tan^{-1}(\frac{93.7}{17.3})\\\alpha=79.5=80

Hence, the angle between both resultant force components is 80 °, meaning that the resultant force direction is positive, above the x-axis.

Now we have to calculate the magnitude of the resultant force since the sum of both resultant force components is equal to the hypotenuse of the formed triangle, we have that:

sin(\alpha)=\frac{y-axisValue}{ResultantForceMagnitude}=\frac{93.7lbs}{ResultantForceMagnitude}\\\\ResultantForceMagnitude=\frac{93.7lbs}{sin(80)}=95.14lbs

So, we have that:

  • Resultant force magnitude is equal to 95.14 lbs
  • Direction is 80° respect to the x-axis.

Have a nice day!

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Step-by-step explanation:

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