<h2>
Range of x </h2><h3>
and x>6</h3><h3>
Step-by-step explanation:</h3>
Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5
The sum of the length of any two sides of a triangle is greater than the length of third side.
Case I
AB + BC > AC
⇔4x +5 +3x -2 > 9x -5
⇔7x + 3 >9x - 5
⇔ 7x -9x > -5 -3
⇔-2x > -8
⇔x <4
Case II
if AB+AC > BC
4x +5 +9x -5> 3x -2
⇔13x >3x -2
⇔ 13x -3x> -2
⇔10x > -2
⇔x >
Case III
AC+BC > AB
⇔9x - 5 +3x - 2 > 4x +5
⇔6x -7 > 4x +5
⇔6x -4x >5+7
⇔2x > 12
⇔x > 6
Answer:
Bottom right
Step-by-step explanation:
Each domain value can only have 1 range value.
Answer:
b= -48
Step-by-step explanation:
by transposing,
43=59+b/3
b/3+59=43
b/3=43-59
b/3= -16
b= -16×3
b= -48
therefore the answer is b= -48
hope it helps!!!
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Answer:
the m angle ABC is 19x+12
Answer:
-11x+12
Step-by-step explanation:
(x^2-4x+3)-(x^2+7x-9)
x^2-x^2-4x-7x+3-(-9)
-11x+3+9
-11x+12