Percent (%) Composition of CuO
Cu = 1 x 50g - Multiply by one as there is one Cu
O = 1 x 12.5g - Multiply by one as there is one O
CuO = 62.5g
% for Cu = 50g over 62.5 multiplied by 100 = 80%
% for O = 12.5g over 62.5 multiplied by 100 = 20%
Final Answer :
<em>Percent (%) Composition of CuO = </em>80% (Cu) & 20% (O)
Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:
C1V1 = C2V2
(6.0M)(2.0mL) = C2(500.0mL)
Therefore, the final concentration, C2 = 0.024M.
<span> The nuclear reactor powers plants to inhale heats that are needed to create/produce steam- (a gas that comes from liquid at its boiling point) The process is called fission. Fission entails the splitting on atoms in the nuclear reactor.
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1: The grass
2: The grasshopper
3: The frog
4: The snake
5: The eagle
Page: 2
The answer is the 2nd one
Page: 3
The owl would because its at the end it would have almost no more sun energy left in whatever it eats.
Hope This Helps :)
The ostrich runs 21 N then goes back by 25 S
The displacement is -4 S
21 - 25 = -4
