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zalisa [80]
3 years ago
5

A certain material has a mass of 12.48 g while occupying 12.48 cm3 of space. What is this material?

Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
5 0
This material has a density of 1 g/cm3.
(since 12.48 g/ 12.48 cm3 = 1 g/cm3)

Therefore, this material is water.
Sliva [168]3 years ago
5 0

Answer: The material is water as it has density of 1g/cm^3  

Explanation:

Density is defined as the mass contained per unit volume.  It is characteristic of a material.

Density=\frac{mass}{Volume}

Given : Mass of object =12.48 grams

Volume of the object = 12.48cm^3

Putting in the values we get:

Density=\frac{12.48g}{12.48cm^3}

Density=1g/cm^3

Thus the density of the material is 1g/cm^3 and material is water which has density of  1g/cm^3.

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Balance the following equation by adding the correct mole numbers.<br>P⁴+Cl²-&gt;PCl³​
marta [7]

Hey there!

P₄ + Cl₂ → PCl₃

First, let's balance Cl.

There are 2 on the left, and 3 on the right.

To balance this, let's put a coefficient of 3 in front of Cl₂ and a coefficient of 2 in front of PCl₃.

P₄ + 3Cl₂ → 2PCl₃

Now we have 6 on the left and 6 on the right.

Next, let's balance P.

There are 4 on the left and 2 on the right.

Let's change the coefficient in front of PCl₃ from 2 to 4.

P₄ + 3Cl₂ → 4PCl₃

There are now 4 P on each side.

However, now Cl is unbalanced, with 6 on the left and 12 on the right.

We can change the coefficient in front of Cl₂ from 3 to 6.

P₄ + 6Cl₂ → 4PCl₃

So now, we have 4 P on each side and 12 C on each side.

This is our final balanced equation.

Hope this helps!

6 0
3 years ago
Why does phosphate act as an environmental contaminant?
Anit [1.1K]

Answer:

Too much phosphorus in the water causes algae to grow faster than ecosystems can handle. Large growths of algae are called algal blooms and they can <u>severely reduce or eliminate oxygen in the water</u>, leading to illnesses in fish and the death of large numbers of fish.

Explanation

Futhermore, with a loss of fish the whole ecosystem will be upset and will be in need of serious recovery.

7 0
2 years ago
A pump separates out Argon atoms from all other atoms in air. If a bottle contains 8.34 x 10^22 atoms of argon what is the mass
puteri [66]

Answer:

55.4g

                                           

Explanation:

Given parameters:

Number of atoms in the bottle = 8.34 x 10²²atoms

Unknown:

Mass of air in the bottle  = ?

Solution:

The given specie is argon.

 Molecular mass of Argon  = 40g/mol

To find the mass of this Argon ;

          Mass  = number of moles x molecular mass;

  Let us find the number of moles of the Argon;

             6.02 x 10²³ atoms can be found in 1 mole of any substance

             8.34 x 10²² atoms will give \frac{8.34 x 10^{22} }{6.02 x 10^{23} }  mole of Argon

                                                        = 0.139mole of Argon

So;

       Mass of argon  = 40g/mol x 0.139mole  = 55.4g

                                           

7 0
2 years ago
A 5.00 gram sample of an oxide of lead PbxOy contains 4.33g of lead. Determine the simplest formula for the compound.
Valentin [98]
PbO2

You have to take the mass of lead in the problem, and divide by the molar mass.
When you do the same with oxygen, you get a number about twice as large as when you divide the mass of lead by the molar mass of lead. This means that the simplest formula  would be PbO2

8 0
3 years ago
An unknown compound was decomposed into 63.2 g carbon, 5.26 g hydrogen, and 41.6 g oxygen. what is its empirical formula?
ira [324]
Step 1:
           Divide mass of each element with its M.mass in order to find out moles.

                       C  =  63.2 g / 12 g/mol  =  Moles  =  5.26 moles

                       H  =  5.26 g / 1.008 g/mol  =  Moles  =  5.21 moles

                       C  =  41.6 g / 16 g/mol  =  Moles  =  2.6 moles

Step 2:
          Select moles of the element with least value and divide all moles of element by it,
                             C                H             O          
                       5.26/2.6  :  5.21/2.6  :  2.6/2.6

                          2.02     :     2.00     :       1

Result:
               Empirical Formula  =     C₂H₂O
4 0
3 years ago
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