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Nezavi [6.7K]
2 years ago
9

What is the pH of 0.166 M triethylammonium chloride, (C2H5)3NHCl. The Kb of triethylamine, (C2H5)3N, is 5.2 x 10-4.?

Chemistry
1 answer:
777dan777 [17]2 years ago
7 0

Answer:

5.7

Explanation:

(C₂H₅)₃NHCl dissociates according to the following equation.

(C₂H₅)₃NHCl ⇒ (C₂H₅)₃NH⁺ + Cl⁻

The molar ratio of (C₂H₅)₃NHCl to (C₂H₅)₃NH⁺ is 1:1. Then, the concentration of (C₂H₅)₃NH⁺ is Ca = 0.166 M.

(C₂H₅)₃NH⁺ is the conjugate acid of (C₂H₅)₃N. Given the Kb of (C₂H₅)₃N, we can calculate Ka for (C₂H₅)₃NH⁺ using the following expression.

Ka × Kb = Kw

Ka = Kw / Kb

Ka = 1.0 × 10⁻¹⁴ / 5.2 × 10⁻⁴

Ka = 1.9 × 10⁻¹¹

(C₂H₅)₃NH⁺ dissociates according to the following equation.

(C₂H₅)₃NH⁺ ⇄ (C₂H₅)₃N + H⁺

We can calculate [H⁺] using the following expression.

[H⁺] = √(Ca × Ka) = √(0.166 × 1.9 × 10⁻¹¹) = 1.8 × 10⁻⁶

The pH is:

pH = -log [H⁺] = -log 1.8 × 10⁻⁶ = 5.7

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Balance the double replacement: <br> Mn(SO4)2 + K2S2O3 =
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        Mn(SO₄)₂ + 2 K₂S₂O₃ ----------> Mn(S₂O₃)₂ + 2 K₂SO₄

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              Mn(SO₄)₂ + K₂S₂O₃ =

Balance Equation = ?

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Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the Sulfur at the reactant side is 6, the number of Sulfurmust be 6 on the product side.

First we Complete the reaction

                  Mn(SO₄)₂ + K₂S₂O₃ ----------> Mn(S₂O₃)₂ + K₂SO₄

Check the chemical equation and count the number of atoms at the reactant side and product side.

If the number of atoms of the reactants equal to the number of atoms of products then the reaction is balanced but if not equal, then reaction is not balanced

Balancing is an trial and error process to get a balance reaction.

First we count the number of atoms of reactant and product

             Mn(SO₄)₂ + K₂S₂O₃ ----------> Mn(S₂O₃)₂ + K₂SO₄

Number of atoms of Reactant:

Mn = 1

S = 4

O = 7

K = 2

Number of atoms of Product:

Mn = 1

S = 5

O = 10

K = 2

So this is not a balance equation as the atoms of the reactant atoms not equal to the number of the product atoms.

As there are 4 Sulfur, and 7 oxygen atoms at reactant side but 5 Sulfur, and 10 oxygen atoms at the product side so we balance this along with other

Balanced Equation:

          Mn(SO₄)₂ + 2 K₂S₂O₃ ----------> Mn(S₂O₃)₂ + 2 K₂SO₄

Now count the number of atoms of reactant and product

Number of atoms of Reactant:

Mn = 1

S = 6

O = 14

K = 4

Number of atoms of Product:

Mn = 1

S = 5

O = 10

K = 2

Now this reaction is balanced as the atoms of the reactant atoms equal to the number of the product atoms.

So,

the Coefficient of  K₂S₂O₃ and K₂SO₄ is 2 in balanced equation

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