Two 1+ ions are needed in order to balance one 2- ion.
P = nRT/V
P = 3.5 x 10^-3 x 0.082 x 298 /0.5
P = 0.171 m Hg
P = 171 mm Hg
hope this helps
Answer:
The answer to your question is 900 g of water vapor
Explanation:
Data
mass of H₂O = ?
mass of butane = 580 g
Balanced chemical reaction
2C₄H₁₀ + 13O₂ ⇒ 8CO₂ + 10H₂O
Process
1.- Calculate the molar weight of butane and water
Butane (C₄H₁₀) = 2[(12 x 4) + (1 x 10)]
= 2[48 + 10]
= 2[58]
= 116 g
Water (H₂O) = 10[(1 x 2) + (1 x 16)]
= 10[2 + 16]
= 10[18]
= 180 g
2.- Use proportions and cross multiplication to find the mass of water vapor
116 g of butane ------------- 180 g of water
580 g of butane ---------- x
x = (580 x 180) / 116
x = 900 g of water vapor
The percentage of sugar in the solution is 1%
To solve this question, we need to find the percentage of 6 out of 600.
Data given;
- mass of sugar = 6g
- mass of solution = 600g
<h3 /><h3>What is Percentage</h3>
This is the rate or proportion of a substance in the total value and multiplied by 100.
The percentage of sugar in the solution is calculated by
The percentage of sugar in the solution is 1%
Learn more about percentage here;
brainly.com/question/251701
