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AnnyKZ [126]
3 years ago
6

Simplify the expression.3y2 – 2y[4y - Y(y– 3)] – [2y(y + 1)-3y(y^2-1)] =​

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0

Answer:

5y^{3} -13y^{2} -5y

Step-by-step explanation:

3y^{2} -2y[4y - y(y-3)] - [2y(y + 1)-3y(y^{2} -1)] \\\\3y^{2} -2y[4y - y^{2} +3y] - [2y^{2} +2y- 3y^{3}+3y] \\\\3y^{2}- 8y^{2}+2y^{3}- 6y^{2}- 2y^{2}- 2y+3y^{3}- 3y\\\\5y^{3}- 13y^{2}- 5y

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