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xenn [34]
3 years ago
6

Jake monthly expenses include a $60 cable bill, a $200 car payment and $120 for car insurance. If he brings home $525 per month,

how much money does Jake have left to spend per month after paying his bills?
Mathematics
2 answers:
Anit [1.1K]3 years ago
5 0

Answer:

he would have 145 dallors after baying his bills


Step-by-step explanation:


il63 [147K]3 years ago
5 0

Jake has 145 dollars left to spend.

How I got this answer:

Add 60, 200 and 120 together. After adding this, you would get 380. Since it asks how much money he has 'left', you subtract 380 from 525, which gives you 145.

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(7-15-3+5-7)×1 step by step​
Tresset [83]

Answer:

-13

Step-by-step explanation:

(7−15−3+5−7)⋅1

Subtract 15 from 7 to get −8.

(−8−3+5−7)×1

Subtract 3 from −8 to get −11.

(−11+5−7)×1

Add −11 and 5 to get −6.

(−6−7)×1

Subtract 7 from −6 to get −13.

−13

6 0
2 years ago
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Please help me ASAP!!!​
Sergeu [11.5K]

Answer: 8

Because 8 - 11 = -3

Hope it helps.

3 0
3 years ago
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The local cable company charges $90 per month for basic and $12 per month for each additional premium cable channel.The function
Alika [10]

Answer:

2 additional premium channels

Step-by-step explanation:

Using the given function, we substitute c(x) = 114 and solve for x:

114 =90 + 12x

Subtract 90 from both sides:

24=12x

Divide both sides by 12:

2=x

So you have ordered 2 additional premium channels.

5 0
3 years ago
Solve.<br> 4(a+2)=14-2(3-2a)<br><br> A. -2<br> B. All real numbers <br> C.-1<br> D. No solution
White raven [17]
4a+8=14-6+4a. 4a+8=8+4a so I think it's B
3 0
3 years ago
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A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

           x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

4 0
3 years ago
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