- The domain of this relationship can be defined as,
0 ≤ x ≤ 60
- The range of this relationship can be defined as,
0 ≤ y ≤ 40
Definition of Domain and Range
The set of all the possible input values for which the provided function is defined is termed as the domain of that function.
The set of all the possible values that a given function can generate as an output is termed as the range of that function.
Forming the Relation
It is given that,
- Jackson wants to purchase 2 shirts and 3 pairs of pants with his gift card
- x represents the cost of the shirts and y represents the cost of the pants
- The limit of the gift card = $120
Thus, the relation formed is given by,
Domain and Range of the Given Relation
We have,
⇒ 
⇒ 
Thus, the domain is given by,
⇒ 
Similarly,
⇒ 
Thus, the range is given by,
⇒ 
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Answer:
change in the total cost for each book printed = $15
cost to get started (before books are bought) = $1200
Step-by-step explanation:
IF the eqn is y = 15x +1200
where y represent the total cost of publishing a book (in dollars) and
x represent the number of copies of the book printed
then cost to get started (before books are bought) can be found by substitute x=0 into the eqn
y = 1200 + 15*0 = $1200
change in the total cost for each book printed will be the difference in total cost at x=0 and x=1
when x=0, y=1200
when x=1, y=1200+15*1=1215
so the change in total cost=$15
Answer:
C = ~50 deg
Step-by-step explanation:
Apply the cosine theorem:
cos(C) = (CA^2 + CB^2 - AB^2)/(2*CA*CB)
= (7.5^2 + 6.5^2 - 6^2)/(2*7.5*6.5)
= 0.6410
=> C = ~50 deg
Hope this helps!
Answer: i don't know you have to figure it out yourself duh.
Step-by-step explanation: This is none of your beeswax
Basically you're solving for both variables here.
I prefer elimination method so that is what I used.
I started off by multiplying each equation in order to get one of the variables at the same value so it would be possible to cancel it out.
Multiplying the first equation by 3 gave me,
12x + 15y = 69
Then I multiplied the second equation by 4,
-12x + 28y = -56
As you can see, it's not possible to cancel out the x variable.
12x + 15y = 69
+(-12x + 28y = -56)
_____________
13y = 13
Then just solve for y which gives you -1.
After you have one variable solved simply insert it into one of the original equations to find the other variable.
4x + 5(-1) = 23
4x - 5 = 23
4x = 28
x = 7.
And there you have it! Hope this helped!
