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2 years ago

Is this symmetrical or asymmetrical? Dont guess!I will mark brainliest if its correct!

Mathematics

1 answer:

lilavasa [31]2 years ago

5 0

Answer:

im just saying this is supposed to help you, this is just flat out cheating, but its d

Step-by-step explanation:

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What are the Properties of a function

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Answer:

A function is a relation in which each possible input value leads to exactly one output value

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3 years ago

The estimated probability of a football player scoring a touchdown during a particular game is 26%. If several simulations of th

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I believe the answer is C

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3 years ago

Read 2 more answers

Determine the equation of the linear function that has a slope of -4 and passes through the point (2,-4). Write the equation in

padilas [110]

Answer:

Part 1) $y=-4x+4$

Part 2) The graph in the attached figure

Step-by-step explanation:

Part 1)

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=-4\\point\ (2,-4)$

substitute in the linear equation

$-4=-4(2)+b$

solve for b

$-4=-8+b\\b=8-4\\b=4$

substitute

$y=-4x+4$

Part 2) Draw the equation

we know that

To graph a line we need two points

we have the y-intercept (0,4) and (2,-4)

Plot the points, connect them and join to draw the line

see the attached figure

7 0

3 years ago

Put the following equation of a line into slope-intercept form, simplifying all fractions. 3y - 40 = 9

Nina [5.8K]

Answer:

3y=49

Step-by-step explanation:

yeppp I'm pretty sure

8 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago