This is the concept of trajectories;
We are required to calculate the time taken for the base ball whose distant to reach the maximum height has been modeled by h=-16t^2+64t+4.2 took to hit the ground. Here we proceed as follows;
At the time when the base ball hits the ground the height,h=0
Thus;
-16t^2+64t+4.2=0
this is a quadratic equation, to solve the quadratic equation we use the formula;
t=[-b+/- sqrt(b^2-4ac)]/(2a)
where;
a=-16,b=64, c=4.2
thus substituting the values in our formula we get:
t=[-64+/-sqrt(64^2-4*(-16)*4.2)]/(-16*2)
t=[-64+/- sqrt(4364.8)]/(-32)
t=[-64+/-66.1]/(-32)
t=4.1 or-0.1
thus the we take the positive value t=4.1 and we conclude that the time taken for the ball to hit the ground was 4.1 seconds
approximatly 223.25 cubic inches
Volume of a sphere = (4/3)*pi*r squared
(4/3)*(3.142)*(53.29)
223.25 cubic inches
Y = mx + b is the equation
m = slope, or 3
b = y-intercept, or 1
y = 3x + 1
is your equation
Answer:
a) $3480
b) $4036.8
Step-by-step explanation:
The compound interest formula is given by:

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.
Suppose that $3000 is placed in an account that pays 16% interest compounded each year.
This means, respectively, that 
So



(a) Find the amount in the account at the end of 1 year.
This is A(1).


(b) Find the amount in the account at the end of 2 years.
This is A(2).

Answer:
Richhhh!!! Thanks for the points!!
Step-by-step explanation: