Volume
of a rectangular box = length x width x height<span>
From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>
<span>
where x is the height of the box or the side of the equal squares from each
corner and turning up the sides
V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x
To maximize the volume, we differentiate the expression of the volume and
equate it to zero.
V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>
<span>x^2 - 50/3x + 50 = 0
Solving for x,
x1 = 12.74 ; Volume = -315.56 (cannot be negative)
x2 = 3.92 ;
Volume = 1056.31So, the answer would be that the maximum volume would be 1056.31 cm^3.</span><span>
</span>
Answer:
x-intercept=(-1,0) y-intercept =(0,-3)
Step-by-step explanation:
I believe the range is 25.
Started with: $60
left with: $10
items bought: 20
60 - 10 = 50 < amount spent
50/20 = amount spent/items bought
= $ 2.50 < each chocolate
you can check this by multiplying the items bought and the amount each item cost to get how much you spent
20 × 2.5 = 50
Stephanie started off with 60 dollars and ended with 10 dollars
60 - 50 = 10
hope this helps :)
