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frutty [35]
2 years ago
13

Having a problem figuring out how to solve these types of math problems, any help would be appreciated. Use substitution to solv

e the system
The explanations provide in ALEKS does not make sense to me.

-3x + y = -11
2X + 5y = 30
Mathematics
2 answers:
Verdich [7]2 years ago
7 0
The two equations can be solve using substitution method. 
<span>-3x + y = -11    .....................(1)
2X + 5y = 30    .....................(2)
</span>
From equation 1,
-3x + y = -11 
y=-11+3x
y=3x-11

Substitute the vale of y in equation 2 with y=3x-11,
2X + 5y = 30
2x + 5(3x-11) = 30
2x + 15x - 55 = 30
17x -55 = 30
17x = 30+55
17x = 85
x =85/17
   =  5

From the equation 1, 
 y=3x-11
Since  x = 5,

y = 3(5) - 11
  = 15 - 11
  = 4

Answer;
     x = 5
     y = 4


garri49 [273]2 years ago
6 0
1) -3x + y= -11
2)2x + 5y = 30

Either both x or both y have to be equal
So 1) can be multiplied by 5 to get y to become 5y

Therefore 1) becomes 3) -15x + 5y = 30


So you do 2) - 3)

To get 17x=85
Divide both sides by 17 to get x=5



Then to get y sub 5 into 2x + 5y= 30


2*5 + 5y = 30

10 + 5y = 30

-10. -10

5y = 20

/5. /5


Y= 4




So you get that y=4 and x=5





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FromTheMoon [43]

Answer:

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Double-Check

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Step-by-step explanation:


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kow [346]
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Strike441 [17]

Answer:

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Step-by-step explanation:

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\frac{a^{m}}{a^{n}} = a^{(m-n)}

Method 1:

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Method 2:

Even if you solve the given problem manually, you'd still get the same answer:

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