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2 years ago

EVALUATE 8+3⋅4 OVER 2 THE ANSWERS ARE 8 10 16 22

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

4 0

The answer is 10 ..............................

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Can someone help me please

klio [65]

X = (23+39)/ 2 = 62/2 = 31

answer
x = 31

5 0

3 years ago

Find the sum of the squares of the roots of 3x^2 + 4x + 12 = 0

Contact [7]

Answer:

-56/9

Step-by-step explanation:

Let p and q be the roots of the equation.

So, here's how we're gonna work it out:

${p}^{2} + {q}^{2} = \\ {p}^{2} + {q}^{2} +2 pq - 2pq = \\ ( {p}^{2} +2pq + {q}^{2}) - 2pq = \\ {(p + q)}^{2} - 2pq$

Vieta's formulas give us the sum and the product of the roots of a quadratic equation. Using them we obtain:

p + q = -b / a = - 4 / 3
p × q = c / a = 12 / 3 = 4

${(p + q)}^{2} - 2pq = \\ {( - \frac{ 4}{3} )}^{2} - 2 \times 4 = \frac{16}{9 } - 8 = \\ \frac{16 - 72}{9} = - \frac{56}{9}$

4 0

3 years ago

How do u put 3 6/60 as a decimal?

pochemuha

3 over 1 + 6 over 60

[3 over 1 × 60 over 60] + 6 over 60

180 over 60 + 6 over 60 ➡ 186 over 60

186 over 60 ➡ 31 over 10

Then we divide 31 from 10 which give you the quotient of 3.1..

(((Meaning ➡ '"3.1" would be your answer)))

6 0

2 years ago

Find the x-coordinates where f ' (x)=0 for f(x)=2x+sin(4x) in the interval [0, pi]

MAVERICK [17]

Answer:

The x-coordinate is \dfrac{\pi}{6}[/tex].

Step-by-step explanation:

We are given a function f(x) as:

$f(x)=2x+\sin (4x)$

Now on differentiating both side with respect to x we get that:

$f'(x)=2+4 \cos (4x)$

When $f'(x)=0$

this means that $2+4\cos (4x)=0\\\\4\cos (4x)=-2\\\\\cos(4x)=\dfrac{-1}{2}$

Hence, cosine function takes the negative value in second and third quadrant but we have to only find the value in the interval $[0,\pi]$ .

also we know that $\cos (\dfrac{2\pi}{3})=\dfrac{-1}{2}$ ----(1) (which lie in the second quadrant)

so on comparing our equation with equation (1) we obtain:

$4x=\dfrac{2\pi}{3}\\\\x=\dfrac{\pi}{6}$

Hence, the x-coordinates where $f'(x)=0$ for $f(x)=2x+\sin(4x)$ is $\dfrac{\pi}{6}$ .

5 0

3 years ago

The diameter of Mercury is approximately 4.9×10^3 kilometers. The diameter of Earth is approximately 1.3×10^4 kilometers. About

JulijaS [17]

$\text {Number of times = } \dfrac{1.3 \times 10^4}{4.9 \times 10^3 }$

$\text {Number of times = } \dfrac{1.3}{4.9} \times 10^{4-3}$

$\text {Number of times = } 0.27 \times 10$

$\text {Number of times = } 2.7$

5 0

2 years ago