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3 years ago

Whats 358 divided by 3 useing compatible numbers

Mathematics

1 answer:

laiz [17]3 years ago

4 0

358/3= 119.33, and the decimal goes on forever. i dont know what you mean by compatible numbers.

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HAVE A NICE DAY WILL GIVE BRAINLST :)

Novosadov [1.4K]

Answer:

1. A

2. C

Step-by-step explanation:

6 0

3 years ago

Need help with this math problem

ladessa [460]

Answer:

m<1: 51

m<2: 61

m<3: 29

Step-by-step explanation:

m<1 = 51, because to find the 3rd angle, you need to add the other two angles and then subtract 180 from that answer.

61 + 68 = 129

180 - 129 = 51

m<2 = 61, because it's a vertical angle, meaning that the angle that's opposite to it exactly, is the same. So since the angle opposite to m<2 is 61, that's what the answer would be.

m<3 = 29, because all you need to do is add 90 and 61, and then subtract 180 by the answer. I got 90 as one of the angle measurements because there's a right triangle, meaning it's 90. Then since we already know what angle 2 is (61) then all you need to do is add:

90 + 61 = 151

Then subtract:

180 - 151 = 29

8 0

4 years ago

368.54 = ( _ x 100) + ( _ x 10) + ( _ x 1/10) + ( _ x 1/100)

SCORPION-xisa [38]

Answer:

$368.54 = 3*100 + 6.8*10 +5*1/10 + 4*100$

Step-by-step explanation:

Given

$368.54 = ( [\ ] * 100) + ( [\ ] * 10) + ( [\ ] * 1/10) + ( [\ ] * 1/100)$

Required

Fill in the gap

The number can be expressed as:

$368.54 = 300 + 60 + 8 +0.5 + 0.04$

Factorize:

$368.54 = 3*100 + 6*10 + 0.8*10 +5*1/10 + 4*100$

Factor out 10 in 6 * 10 + 0.8 * 10

$368.54 = 3*100 + [6 + 0.8]*10 +5*1/10 + 4*100$

$368.54 = 3*100 + 6.8*10 +5*1/10 + 4*100$

Solved

4 0

3 years ago

Length of a tennis court:26yd length of a table tennis table:9ft what would be the ratio

Alex17521 [72]

9 colon 26 beacuse its a ratio

3 0

3 years ago

Read 2 more answers

Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es

Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4× $(1/2)^{\infty}$

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

$S_{\infty} = \dfrac{a}{1 - r}$

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

$La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty} = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2$

La suma al infinito de las áreas de los cuadrados, $S_{\infty}$ = 8 in.²

7 0

3 years ago